Viking_Hippie@lemmy.dbzer0.com to Science Memes@mander.xyzEnglish · 1 month agoWhoops!lemmy.dbzer0.comimagemessage-square38linkfedilinkarrow-up11.03Karrow-down10
arrow-up11.03Karrow-down1imageWhoops!lemmy.dbzer0.comViking_Hippie@lemmy.dbzer0.com to Science Memes@mander.xyzEnglish · 1 month agomessage-square38linkfedilink
minus-squareNot_mikey@lemmy.dbzer0.comlinkfedilinkEnglisharrow-up28·1 month agoTetraoxidane (H2O4) is very unstable by itself, and I doubt adding a uranium into the mix would stabilize it
minus-squareOwOarchist@pawb.sociallinkfedilinkEnglisharrow-up22·1 month agoHm… I’m guessing that adding Uranium to that would make it quickly oxidize, and instead of H2O4U, you’d get mostly U3O8 (the most stable Uranium oxide) and a bunch of H2O and Hydrogen gas.
minus-squareFluke@feddit.uklinkfedilinkEnglisharrow-up14·1 month agoAnd a lot of heat. If I had to guess, I’d bet on that being a… “rather energetic” exothermic reaction.
minus-squarefartographer@lemmy.worldlinkfedilinkEnglisharrow-up12·1 month agoSurely if you shook the bottle well, the ingredients would recombine like a vinaigrette, and the intended flavor could be appreciated.
minus-squarewonderingwanderer@sopuli.xyzlinkfedilinkEnglisharrow-up8·1 month agoNo way to know until you try
minus-squareAniki@feddit.orglinkfedilinkEnglisharrow-up1·29 days agono way to know but a good way to guess
minus-squarewonderingwanderer@sopuli.xyzlinkfedilinkEnglisharrow-up1·29 days agoBy counting valence electrons?
Tetraoxidane (H2O4) is very unstable by itself, and I doubt adding a uranium into the mix would stabilize it
Hm… I’m guessing that adding Uranium to that would make it quickly oxidize, and instead of H2O4U, you’d get mostly U3O8 (the most stable Uranium oxide) and a bunch of H2O and Hydrogen gas.
And a lot of heat. If I had to guess, I’d bet on that being a… “rather energetic” exothermic reaction.
What is heat but shaken atoms?
Surely if you shook the bottle well, the ingredients would recombine like a vinaigrette, and the intended flavor could be appreciated.
Refreshing!
No way to know until you try
no way to know but a good way to guess
By counting valence electrons?